Factor polynomial $$ 9v^{4}-100 $$
Answer
$$ 9v^{4}-100 = ( 3v^{2}-10 )( 3v^{2}+10 ) $$
Explanation
Rewrite $ 9v^{4}-100 $ as:
$$ 9v^{4}-100 = (3v^{2})^2 - (10)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 3v^{2} $ and $ II = 10 $ , we have:
$$ 9v^{4}-100 = (3v^{2})^2 - (10)^2 = ( 3v^{2}-10 ) ( 3v^{2}+10 ) $$This page was created using
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