Factor polynomial $$ 9u^{2}v^{4}+6uv^{2}+1 $$
Answer
$$ 9u^{2}v^{4}+6uv^{2}+1 = (3uv^{2}+1)(3uv^{2}+1) $$
Explanation
Note that the polynomial $ 9u^2v^4+6uv^2+1 $ is a perfect square trinomial, so we will use the following formula.
$$ A^2 + 2AB + B^2 = (A + B)^2 $$In this example we have $ \color{blue}{ A = 3uv^2 } $ and $ \color{red}{ B = 1 } $ so,
$$ 9u^2v^4+6uv^2+1 = ( \color{blue}{ 3uv^2 } + \color{red}{ 1 } )^2 $$This page was created using
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