Factor polynomial $$ 9u^{2}-12uv+4v^{2} $$
Answer
$$ 9u^{2}-12uv+4v^{2} = (3u-2v)(3u-2v) $$
Explanation
Note that the polynomial $ 9u^2-12uv+4v^2 $ is a perfect square trinomial, so we will use the following formula.
$$ A^2 - 2AB + B^2 = (A - B)^2 $$In this example we have $ \color{blue}{ A = 3u } $ and $ \color{red}{ B = 2v } $ so,
$$ 9u^2-12uv+4v^2 = ( \color{blue}{ 3u } - \color{red}{ 2v } )^2 $$This page was created using
Polynomial Factoring Calculator