Factor polynomial $$ 9t^{3}-6t^{2}-24t+16 $$
Answer
$$ 9t^{3}-6t^{2}-24t+16 = ( 3t^{2}-8 )( 3t-2 ) $$
Explanation
To factor $ 9t^{3}-6t^{2}-24t+16 $ we can use factoring by grouping:
Group $ \color{blue}{ 9x^{3} }$ with $ \color{blue}{ -6x^{2} }$ and $ \color{red}{ -24x }$ with $ \color{red}{ 16 }$ then factor each group.
$$ \begin{aligned} 9t^{3}-6t^{2}-24t+16 = ( \color{blue}{ 9x^{3}-6x^{2} } ) + ( \color{red}{ -24x+16 }) &= \\ &= \color{blue}{ 3x^{2}( 3x-2 )} + \color{red}{ -8( 3x-2 ) } = \\ &= (3x^{2}-8)(3x-2) \end{aligned} $$This page was created using
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