Factor polynomial $$ 9p^{2}-9 $$
Answer
$$ 9p^{2}-9 = 9( p-1 )( p+1 ) $$
Explanation
Step 1 :
After factoring out $ 9 $ we have:
$$ 9p^{2}-9 = 9 ( p^{2}-1 ) $$Step 2 :
Rewrite $ p^{2}-1 $ as:
$$ p^{2}-1 = (p)^2 - (1)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = p $ and $ II = 1 $ , we have:
$$ p^{2}-1 = (p)^2 - (1)^2 = ( p-1 ) ( p+1 ) $$This page was created using
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