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Factor polynomial $$ 9n^{6}+72n^{4}-90n^{3}+18n^{2} $$
Answer
$$ 9n^{6}+72n^{4}-90n^{3}+18n^{2} = 9n^{2}( n^{4}+8n^{2}-10n+2 ) $$
Explanation
After factoring out $ 9n^{2} $ we have:
$$ 9n^{6}+72n^{4}-90n^{3}+18n^{2} = 9n^{2} ( n^{4}+8n^{2}-10n+2 ) $$