Factor polynomial $$ 9m^{4}-4n^{2} $$
Answer
$$ 9m^{4}-4n^{2} = (3m^{2}+2n)(3m^{2}-2n) $$
Explanation
Rewrite $ 9m^4-4n^2 $ as:
$$ \color{blue}{ 9m^4-4n^2 = (3m^2)^2 - (2n)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 3m^2 $ and $ II = 2n $ , we have:
$$ 9m^4-4n^2 = (3m^2)^2 - (2n)^2 = ( 3m^2-2n ) ( 3m^2+2n ) $$This page was created using
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