Factor polynomial $9 a^{2} - 24 ab + 16 b^{2}$

Answer

$9 a^{2} - 24 ab + 16 b^{2} = (3 a - 4 b) (3 a - 4 b)$

Explanation

Note that the polynomial $9 a^{2} - 24 ab + 16 b^{2}$ is a perfect square trinomial, so we will use the following formula.

A^{2} - 2 A B + B^{2} = (A - B)^{2}

In this example we have $A = 3 a$ and $B = 4 b$ so,

9 a^{2} - 24 ab + 16 b^{2} = (3 a - 4 b)^{2}

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Factor polynomial 9a2−24ab+16b2

9a2−24ab+16b2=(3a−4b)(3a−4b)

Factor polynomial $9 a^{2} - 24 ab + 16 b^{2}$

$9 a^{2} - 24 ab + 16 b^{2} = (3 a - 4 b) (3 a - 4 b)$