Factor polynomial $$ 98x^{3}-18x $$
Answer
$$ 98x^{3}-18x = 2x( 7x-3 )( 7x+3 ) $$
Explanation
Step 1 :
After factoring out $ 2x $ we have:
$$ 98x^{3}-18x = 2x ( 49x^{2}-9 ) $$Step 2 :
Rewrite $ 49x^{2}-9 $ as:
$$ 49x^{2}-9 = (7x)^2 - (3)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 7x $ and $ II = 3 $ , we have:
$$ 49x^{2}-9 = (7x)^2 - (3)^2 = ( 7x-3 ) ( 7x+3 ) $$This page was created using
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