Factor polynomial $$ 90n^{5}+40n^{4}+40n^{3}-70n^{2} $$
Answer
$$ 90n^{5}+40n^{4}+40n^{3}-70n^{2} = 10n^{2}( 9n^{3}+4n^{2}+4n-7 ) $$
Explanation
After factoring out $ 10n^{2} $ we have:
$$ 90n^{5}+40n^{4}+40n^{3}-70n^{2} = 10n^{2} ( 9n^{3}+4n^{2}+4n-7 ) $$This page was created using
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