Rewrite $ -100x^{2}+9 $ as:
$$ -100x^{2}+9 = 9 -100x^2 = (3)^2 - (10x)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 3 $ and $ II = 10x $ , we have:
$$ -100x^{2}+9 = (3)^2 - (10x)^2 = ( -10x+3 ) ( 10x+3 ) $$