Factor polynomial $$ 8p^{3}+729q^{3} $$
Answer
$$ 8p^{3}+729q^{3} = (2p+9q)(4p^{2}-18pq+81q^{2}) $$
Explanation
To factor $ 8p^{3}+729q^{3} $ we can use sum of cubes formula:
$$ I^3 + II^3 = (I + II) (I^2 - I \cdot II + II^2)$$After putting $ I = 2p $ and $ II = 9q $ , we have:
$$ 8p^{3}+729q^{3} = ( 2p+9q ) ( 4p^{2}-18pq+81q^{2} ) $$This page was created using
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