Factor polynomial $$ 8a^{3}+27b^{3} $$
Answer
$$ 8a^{3}+27b^{3} = (2a+3b)(4a^{2}-6ab+9b^{2}) $$
Explanation
To factor $ 8a^{3}+27b^{3} $ we can use sum of cubes formula:
$$ I^3 + II^3 = (I + II) (I^2 - I \cdot II + II^2)$$After putting $ I = 2a $ and $ II = 3b $ , we have:
$$ 8a^{3}+27b^{3} = ( 2a+3b ) ( 4a^{2}-6ab+9b^{2} ) $$This page was created using
Polynomial Factoring Calculator