Factor polynomial $$ 81x^{2}-49 $$
Answer
$$ 81x^{2}-49 = ( 9x-7 )( 9x+7 ) $$
Explanation
Rewrite $ 81x^{2}-49 $ as:
$$ 81x^{2}-49 = (9x)^2 - (7)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 9x $ and $ II = 7 $ , we have:
$$ 81x^{2}-49 = (9x)^2 - (7)^2 = ( 9x-7 ) ( 9x+7 ) $$This page was created using
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