Factor polynomial $$ 81-100x^{6}y^{6} $$
Answer
$$ 81-100x^{6}y^{6} = (9+10x^{3}y^{3})(9-10x^{3}y^{3}) $$
Explanation
Rewrite $ 81-100x^6y^6 $ as:
$$ \color{blue}{ 81-100x^6y^6 = (9)^2 - (10x^3y^3)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 9 $ and $ II = 10x^3y^3 $ , we have:
$$ 81-100x^6y^6 = (9)^2 - (10x^3y^3)^2 = ( 9-10x^3y^3 ) ( 9+10x^3y^3 ) $$This page was created using
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