Factor polynomial $$ 75r^{2}-48 $$
Answer
$$ 75r^{2}-48 = 3( 5r-4 )( 5r+4 ) $$
Explanation
Step 1 :
After factoring out $ 3 $ we have:
$$ 75r^{2}-48 = 3 ( 25r^{2}-16 ) $$Step 2 :
Rewrite $ 25r^{2}-16 $ as:
$$ 25r^{2}-16 = (5r)^2 - (4)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 5r $ and $ II = 4 $ , we have:
$$ 25r^{2}-16 = (5r)^2 - (4)^2 = ( 5r-4 ) ( 5r+4 ) $$This page was created using
Polynomial Factoring Calculator