Factor polynomial $$ 72x^{2}y-50y $$
Answer
$$ 72x^{2}y-50y = 2y(6x+5)(6x-5) $$
Explanation
Step 1 :
Factor out common factor $ \color{blue}{ 2y } $:
$$ 72x^2y-50y = 2y ( 36x^2-25 ) $$Step 2 :
Rewrite $ 36x^2-25 $ as:
$$ \color{blue}{ 36x^2-25 = (6x)^2 - (5)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 6x $ and $ II = 5 $ , we have:
$$ 36x^2-25 = (6x)^2 - (5)^2 = ( 6x-5 ) ( 6x+5 ) $$This page was created using
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