Factor polynomial $$ 72x^{2}-50y^{2} $$
Answer
$$ 72x^{2}-50y^{2} = 2(6x+5y)(6x-5y) $$
Explanation
Step 1 :
Factor out common factor $ \color{blue}{ 2 } $:
$$ 72x^2-50y^2 = 2 ( 36x^2-25y^2 ) $$Step 2 :
Rewrite $ 36x^2-25y^2 $ as:
$$ \color{blue}{ 36x^2-25y^2 = (6x)^2 - (5y)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 6x $ and $ II = 5y $ , we have:
$$ 36x^2-25y^2 = (6x)^2 - (5y)^2 = ( 6x-5y ) ( 6x+5y ) $$This page was created using
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