Factor polynomial $6 y^{4} + 7 t y^{3} - 20 t^{2} y^{2}$

Answer

$6 y^{4} + 7 t y^{3} - 20 t^{2} y^{2} = y^{2} (- 4 t + 3 y) (5 t + 2 y)$

Explanation

Step 1 :

Factor out common factor $y^{2}$ :

6 y^{4} + 7 t y^{3} - 20 t^{2} y^{2} = y^{2} (6 y^{2} + 7 t y - 20 t^{2})

Step 2 :

$6 y^{2} + 7 t y - 20 t^{2}$ can be written as

6 y^{2} + 7 t y - 20 t^{2} = (- 4 t + 3 y) (5 t + 2 y)

The explanation for this step cannot be generated.

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Factor polynomial 6y4+7ty3−20t2y2

6y4+7ty3−20t2y2=y2(−4t+3y)(5t+2y)

Factor polynomial $6 y^{4} + 7 t y^{3} - 20 t^{2} y^{2}$

$6 y^{4} + 7 t y^{3} - 20 t^{2} y^{2} = y^{2} (- 4 t + 3 y) (5 t + 2 y)$