Factor polynomial $$ 6y^{3}+5y^{2}+42y+35 $$
Answer
$$ 6y^{3}+5y^{2}+42y+35 = ( y^{2}+7 )( 6y+5 ) $$
Explanation
To factor $ 6y^{3}+5y^{2}+42y+35 $ we can use factoring by grouping:
Group $ \color{blue}{ 6x^{3} }$ with $ \color{blue}{ 5x^{2} }$ and $ \color{red}{ 42x }$ with $ \color{red}{ 35 }$ then factor each group.
$$ \begin{aligned} 6y^{3}+5y^{2}+42y+35 = ( \color{blue}{ 6x^{3}+5x^{2} } ) + ( \color{red}{ 42x+35 }) &= \\ &= \color{blue}{ x^{2}( 6x+5 )} + \color{red}{ 7( 6x+5 ) } = \\ &= (x^{2}+7)(6x+5) \end{aligned} $$This page was created using
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