Factor polynomial $$ 6x^{2}-17x-3 $$

$$ 6x^{2}-17x-3 = ( x-3 )( 6x+1 ) $$

Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:

$$ a = 6 , b = -17 ~ \text{ and } ~ c = -3 $$

Step 2: Multiply the leading coefficient $\color{blue}{ a = 6 }$ by the constant term $\color{blue}{c = -3} $.

$$ a \cdot c = -18 $$

Step 3: Find out two numbers that multiply to $ a \cdot c = -18 $ and add to $ b = -17 $.

Step 4: All pairs of numbers with a product of $ -18 $ are:

PRODUCT = -18
-1     18	1     -18
-2     9	2     -9
-3     6	3     -6

Step 5: Find out which factor pair sums up to $\color{blue}{ b = -17 }$

PRODUCT = -18 and SUM = -17
-1     18	1     -18
-2     9	2     -9
-3     6	3     -6

Step 6: Replace middle term $ -17 x $ with $ x-18x $:

$$ 6x^{2}-17x-3 = 6x^{2}+x-18x-3 $$

Step 7: Apply factoring by grouping. Factor $ x $ out of the first two terms and $ -3 $ out of the last two terms.

$$ 6x^{2}+x-18x-3 = x\left(6x+1\right) -3\left(6x+1\right) = \left(x-3\right) \left(6x+1\right) $$

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