Factor polynomial $$ 6x^{2}-11x-10 $$

$$ 6x^{2}-11x-10 = ( 2x-5 )( 3x+2 ) $$

Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:

$$ a = 6 , b = -11 ~ \text{ and } ~ c = -10 $$

Step 2: Multiply the leading coefficient $\color{blue}{ a = 6 }$ by the constant term $\color{blue}{c = -10} $.

$$ a \cdot c = -60 $$

Step 3: Find out two numbers that multiply to $ a \cdot c = -60 $ and add to $ b = -11 $.

Step 4: All pairs of numbers with a product of $ -60 $ are:

PRODUCT = -60
-1     60	1     -60
-2     30	2     -30
-3     20	3     -20
-4     15	4     -15
-5     12	5     -12
-6     10	6     -10

Step 5: Find out which factor pair sums up to $\color{blue}{ b = -11 }$

PRODUCT = -60 and SUM = -11
-1     60	1     -60
-2     30	2     -30
-3     20	3     -20
-4     15	4     -15
-5     12	5     -12
-6     10	6     -10

Step 6: Replace middle term $ -11 x $ with $ 4x-15x $:

$$ 6x^{2}-11x-10 = 6x^{2}+4x-15x-10 $$

Step 7: Apply factoring by grouping. Factor $ 2x $ out of the first two terms and $ -5 $ out of the last two terms.

$$ 6x^{2}+4x-15x-10 = 2x\left(3x+2\right) -5\left(3x+2\right) = \left(2x-5\right) \left(3x+2\right) $$

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