Factor polynomial $$ 6u^{3}-18u^{2}-u+3 $$
Answer
$$ 6u^{3}-18u^{2}-u+3 = ( 6u^{2}-1 )( u-3 ) $$
Explanation
To factor $ 6u^{3}-18u^{2}-u+3 $ we can use factoring by grouping:
Group $ \color{blue}{ 6x^{3} }$ with $ \color{blue}{ -18x^{2} }$ and $ \color{red}{ -x }$ with $ \color{red}{ 3 }$ then factor each group.
$$ \begin{aligned} 6u^{3}-18u^{2}-u+3 = ( \color{blue}{ 6x^{3}-18x^{2} } ) + ( \color{red}{ -x+3 }) &= \\ &= \color{blue}{ 6x^{2}( x-3 )} + \color{red}{ -1( x-3 ) } = \\ &= (6x^{2}-1)(x-3) \end{aligned} $$This page was created using
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