To factor $ 6p^{3}-9p^{2}-2p+3 $ we can use factoring by grouping:
Group $ \color{blue}{ 6x^{3} }$ with $ \color{blue}{ -9x^{2} }$ and $ \color{red}{ -2x }$ with $ \color{red}{ 3 }$ then factor each group.
$$ \begin{aligned} 6p^{3}-9p^{2}-2p+3 = ( \color{blue}{ 6x^{3}-9x^{2} } ) + ( \color{red}{ -2x+3 }) &= \\ &= \color{blue}{ 3x^{2}( 2x-3 )} + \color{red}{ -1( 2x-3 ) } = \\ &= (3x^{2}-1)(2x-3) \end{aligned} $$