Factor polynomial $$ 6g^{2}+22g+16 $$

$$ 6g^{2}+22g+16 = 2( g+1 )( 3g+8 ) $$

Step 1 :

After factoring out $ 2 $ we have:

$$ 6g^{2}+22g+16 = 2 ( 3g^{2}+11g+8 ) $$

Step 2 :

Step 2: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:

$$ a = 3 , b = 11 ~ \text{ and } ~ c = 8 $$

Step 3: Multiply the leading coefficient $\color{blue}{ a = 3 }$ by the constant term $\color{blue}{c = 8} $.

$$ a \cdot c = 24 $$

Step 4: Find out two numbers that multiply to $ a \cdot c = 24 $ and add to $ b = 11 $.

Step 5: All pairs of numbers with a product of $ 24 $ are:

PRODUCT = 24
1     24	-1     -24
2     12	-2     -12
3     8	-3     -8
4     6	-4     -6

Step 6: Find out which factor pair sums up to $\color{blue}{ b = 11 }$

PRODUCT = 24 and SUM = 11
1     24	-1     -24
2     12	-2     -12
3     8	-3     -8
4     6	-4     -6

Step 7: Replace middle term $ 11 x $ with $ 8x+3x $:

$$ 3x^{2}+11x+8 = 3x^{2}+8x+3x+8 $$

Step 8: Apply factoring by grouping. Factor $ x $ out of the first two terms and $ 1 $ out of the last two terms.

$$ 3x^{2}+8x+3x+8 = x\left(3x+8\right) + 1\left(3x+8\right) = \left(x+1\right) \left(3x+8\right) $$

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