Factor polynomial $$ 6b^{2}+66b+60 $$

$$ 6b^{2}+66b+60 = 6( b+1 )( b+10 ) $$

Step 1 :

After factoring out $ 6 $ we have:

$$ 6b^{2}+66b+60 = 6 ( b^{2}+11b+10 ) $$

Step 2 :

Step 2: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:

$$ \color{blue}{ b = 11 } ~ \text{ and } ~ \color{red}{ c = 10 }$$

Now we must discover two numbers that sum up to $ \color{blue}{ 11 } $ and multiply to $ \color{red}{ 10 } $.

Step 3: Find out pairs of numbers with a product of $\color{red}{ c = 10 }$.

PRODUCT = 10
1     10	-1     -10
2     5	-2     -5

Step 4: Find out which pair sums up to $\color{blue}{ b = 11 }$

PRODUCT = 10 and SUM = 11
1     10	-1     -10
2     5	-2     -5

Step 5: Put 1 and 10 into placeholders to get factored form.

$$ \begin{aligned} b^{2}+11b+10 & = (x + \color{orangered}{\square} )(x + \color{orangered}{\square}) \\ b^{2}+11b+10 & = (x + 1)(x + 10) \end{aligned} $$

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