Factor polynomial $$ 64x^{2}-81z^{10} $$
Answer
$$ 64x^{2}-81z^{10} = (8x+9z^{5})(8x-9z^{5}) $$
Explanation
Rewrite $ 64x^2-81z^10 $ as:
$$ \color{blue}{ 64x^2-81z^10 = (8x)^2 - (9z^5)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 8x $ and $ II = 9z^5 $ , we have:
$$ 64x^2-81z^10 = (8x)^2 - (9z^5)^2 = ( 8x-9z^5 ) ( 8x+9z^5 ) $$This page was created using
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