Factor polynomial $$ 64a^{3}+b^{3} $$
Answer
$$ 64a^{3}+b^{3} = (4a+b)(16a^{2}-4ab+b^{2}) $$
Explanation
To factor $ 64a^{3}+b^{3} $ we can use sum of cubes formula:
$$ I^3 + II^3 = (I + II) (I^2 - I \cdot II + II^2)$$After putting $ I = 4a $ and $ II = b $ , we have:
$$ 64a^{3}+b^{3} = ( 4a+b ) ( 16a^{2}-4ab+b^{2} ) $$This page was created using
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