Factor polynomial $$ -49x^{2}+64 $$
Answer
$$ -49x^{2}+64 = ( -7x+8 )( 7x+8 ) $$
Explanation
Rewrite $ -49x^{2}+64 $ as:
$$ -49x^{2}+64 = 64 -49x^2 = (8)^2 - (7x)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 8 $ and $ II = 7x $ , we have:
$$ -49x^{2}+64 = (8)^2 - (7x)^2 = ( -7x+8 ) ( 7x+8 ) $$This page was created using
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