It seems that $ 5x^{2}+32x-160 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 5 }$ by the constant term $\color{blue}{c = -160} $.
$$ a \cdot c = -800 $$Step 3: Find out two numbers that multiply to $ a \cdot c = -800 $ and add to $ b = 32 $.
Step 4: All pairs of numbers with a product of $ -800 $ are:
PRODUCT = -800 | |
-1 800 | 1 -800 |
-2 400 | 2 -400 |
-4 200 | 4 -200 |
-5 160 | 5 -160 |
-8 100 | 8 -100 |
-10 80 | 10 -80 |
-16 50 | 16 -50 |
-20 40 | 20 -40 |
-25 32 | 25 -32 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 32 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ 32 }$, we conclude the polynomial cannot be factored.