Factor polynomial $$ 5x^{2}-4x+16 $$

It seems that $ 5x^{2}-4x+16 $ cannot be factored out.

Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:

Step 2: Multiply the leading coefficient $\color{blue}{ a = 5 }$ by the constant term $\color{blue}{c = 16} $.

Step 3: Find out two numbers that multiply to $ a \cdot c = 80 $ and add to $ b = -4 $.

Step 4: All pairs of numbers with a product of $ 80 $ are:

Step 5: Find out which factor pair sums up to $\color{blue}{ b = -4 }$

Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ -4 }$, we conclude the polynomial cannot be factored.