Factor polynomial $$ 5p^{3}+33p^{2}-14p $$

$$ 5p^{3}+33p^{2}-14p = p( 5p-2 )( p+7 ) $$

Step 1 :

After factoring out $ p $ we have:

$$ 5p^{3}+33p^{2}-14p = p ( 5p^{2}+33p-14 ) $$

Step 2 :

Step 2: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:

$$ a = 5 , b = 33 ~ \text{ and } ~ c = -14 $$

Step 3: Multiply the leading coefficient $\color{blue}{ a = 5 }$ by the constant term $\color{blue}{c = -14} $.

$$ a \cdot c = -70 $$

Step 4: Find out two numbers that multiply to $ a \cdot c = -70 $ and add to $ b = 33 $.

Step 5: All pairs of numbers with a product of $ -70 $ are:

PRODUCT = -70
-1     70	1     -70
-2     35	2     -35
-5     14	5     -14
-7     10	7     -10

Step 6: Find out which factor pair sums up to $\color{blue}{ b = 33 }$

PRODUCT = -70 and SUM = 33
-1     70	1     -70
-2     35	2     -35
-5     14	5     -14
-7     10	7     -10

Step 7: Replace middle term $ 33 x $ with $ 35x-2x $:

$$ 5x^{2}+33x-14 = 5x^{2}+35x-2x-14 $$

Step 8: Apply factoring by grouping. Factor $ 5x $ out of the first two terms and $ -2 $ out of the last two terms.

$$ 5x^{2}+35x-2x-14 = 5x\left(x+7\right) -2\left(x+7\right) = \left(5x-2\right) \left(x+7\right) $$

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