Step 1 :
After factoring out $ 2 $ we have:
$$ 50x^{2}-72 = 2 ( 25x^{2}-36 ) $$Step 2 :
Rewrite $ 25x^{2}-36 $ as:
$$ 25x^{2}-36 = (5x)^2 - (6)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 5x $ and $ II = 6 $ , we have:
$$ 25x^{2}-36 = (5x)^2 - (6)^2 = ( 5x-6 ) ( 5x+6 ) $$