Factor polynomial $$ 4x^{3}+8x^{2}-3x-6 $$
Answer
$$ 4x^{3}+8x^{2}-3x-6 = ( 4x^{2}-3 )( x+2 ) $$
Explanation
To factor $ 4x^{3}+8x^{2}-3x-6 $ we can use factoring by grouping:
Group $ \color{blue}{ 4x^{3} }$ with $ \color{blue}{ 8x^{2} }$ and $ \color{red}{ -3x }$ with $ \color{red}{ -6 }$ then factor each group.
$$ \begin{aligned} 4x^{3}+8x^{2}-3x-6 = ( \color{blue}{ 4x^{3}+8x^{2} } ) + ( \color{red}{ -3x-6 }) &= \\ &= \color{blue}{ 4x^{2}( x+2 )} + \color{red}{ -3( x+2 ) } = \\ &= (4x^{2}-3)(x+2) \end{aligned} $$This page was created using
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