Factor polynomial $$ 4x^{3}+7x^{2}+36x+63 $$
Answer
$$ 4x^{3}+7x^{2}+36x+63 = ( x^{2}+9 )( 4x+7 ) $$
Explanation
To factor $ 4x^{3}+7x^{2}+36x+63 $ we can use factoring by grouping:
Group $ \color{blue}{ 4x^{3} }$ with $ \color{blue}{ 7x^{2} }$ and $ \color{red}{ 36x }$ with $ \color{red}{ 63 }$ then factor each group.
$$ \begin{aligned} 4x^{3}+7x^{2}+36x+63 = ( \color{blue}{ 4x^{3}+7x^{2} } ) + ( \color{red}{ 36x+63 }) &= \\ &= \color{blue}{ x^{2}( 4x+7 )} + \color{red}{ 9( 4x+7 ) } = \\ &= (x^{2}+9)(4x+7) \end{aligned} $$This page was created using
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