Factor polynomial $$ 4x^{3}-3x^{2}+28x-21 $$
Answer
$$ 4x^{3}-3x^{2}+28x-21 = ( x^{2}+7 )( 4x-3 ) $$
Explanation
To factor $ 4x^{3}-3x^{2}+28x-21 $ we can use factoring by grouping:
Group $ \color{blue}{ 4x^{3} }$ with $ \color{blue}{ -3x^{2} }$ and $ \color{red}{ 28x }$ with $ \color{red}{ -21 }$ then factor each group.
$$ \begin{aligned} 4x^{3}-3x^{2}+28x-21 = ( \color{blue}{ 4x^{3}-3x^{2} } ) + ( \color{red}{ 28x-21 }) &= \\ &= \color{blue}{ x^{2}( 4x-3 )} + \color{red}{ 7( 4x-3 ) } = \\ &= (x^{2}+7)(4x-3) \end{aligned} $$This page was created using
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