It seems that $ 4x^{2}+4x+65 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 4 }$ by the constant term $\color{blue}{c = 65} $.
$$ a \cdot c = 260 $$Step 3: Find out two numbers that multiply to $ a \cdot c = 260 $ and add to $ b = 4 $.
Step 4: All pairs of numbers with a product of $ 260 $ are:
PRODUCT = 260 | |
1 260 | -1 -260 |
2 130 | -2 -130 |
4 65 | -4 -65 |
5 52 | -5 -52 |
10 26 | -10 -26 |
13 20 | -13 -20 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 4 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ 4 }$, we conclude the polynomial cannot be factored.