Factor polynomial $$ 4x^{2}+36x-56 $$

$$ 4x^{2}+36x-56 = 4( x^{2}+9x-14 ) $$

Step 1 :

After factoring out $ 4 $ we have:

$$ 4x^{2}+36x-56 = 4 ( x^{2}+9x-14 ) $$

Step 2 :

Step 2: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:

$$ \color{blue}{ b = 9 } ~ \text{ and } ~ \color{red}{ c = -14 }$$

Now we must discover two numbers that sum up to $ \color{blue}{ 9 } $ and multiply to $ \color{red}{ -14 } $.

Step 3: Find out pairs of numbers with a product of $\color{red}{ c = -14 }$.

PRODUCT = -14
-1     14	1     -14
-2     7	2     -7

Step 4: Because none of these pairs will give us a sum of $ \color{blue}{ 9 }$, we conclude the polynomial cannot be factored.

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