Factor polynomial $$ 4x^{2}+11x+6 $$

$$ 4x^{2}+11x+6 = ( 4x+3 )( x+2 ) $$

Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:

$$ a = 4 , b = 11 ~ \text{ and } ~ c = 6 $$

Step 2: Multiply the leading coefficient $\color{blue}{ a = 4 }$ by the constant term $\color{blue}{c = 6} $.

$$ a \cdot c = 24 $$

Step 3: Find out two numbers that multiply to $ a \cdot c = 24 $ and add to $ b = 11 $.

Step 4: All pairs of numbers with a product of $ 24 $ are:

PRODUCT = 24
1     24	-1     -24
2     12	-2     -12
3     8	-3     -8
4     6	-4     -6

Step 5: Find out which factor pair sums up to $\color{blue}{ b = 11 }$

PRODUCT = 24 and SUM = 11
1     24	-1     -24
2     12	-2     -12
3     8	-3     -8
4     6	-4     -6

Step 6: Replace middle term $ 11 x $ with $ 8x+3x $:

$$ 4x^{2}+11x+6 = 4x^{2}+8x+3x+6 $$

Step 7: Apply factoring by grouping. Factor $ 4x $ out of the first two terms and $ 3 $ out of the last two terms.

$$ 4x^{2}+8x+3x+6 = 4x\left(x+2\right) + 3\left(x+2\right) = \left(4x+3\right) \left(x+2\right) $$

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