It seems that $ 4x^{2}-5x+7 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 4 }$ by the constant term $\color{blue}{c = 7} $.
$$ a \cdot c = 28 $$Step 3: Find out two numbers that multiply to $ a \cdot c = 28 $ and add to $ b = -5 $.
Step 4: All pairs of numbers with a product of $ 28 $ are:
PRODUCT = 28 | |
1 28 | -1 -28 |
2 14 | -2 -14 |
4 7 | -4 -7 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = -5 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ -5 }$, we conclude the polynomial cannot be factored.