Factor polynomial $$ 4x^{2}-20xy-7x+35y $$
Answer
$$ 4x^{2}-20xy-7x+35y = (4x-7)(x-5y) $$
Explanation
To factor $ 4x^2-20xy-7x+35y $ we can use factoring by grouping.
Group $ \color{blue}{ 4x^2 }$ with $ \color{blue}{ -20xy }$ and $ \color{red}{ -7x }$ with $ \color{red}{ 35y }$ then factor each group.
$$ \begin{aligned} 4x^2-20xy-7x+35y &= ( \color{blue}{ 4x^2-20xy } ) + ( \color{red}{ -7x+35y }) = \\ &= \color{blue}{ 4x( x-5y )} \color{red}{ -7( x-5y ) } = \\ &= (4x-7)(x-5y) \end{aligned} $$This page was created using
Polynomial Factoring Calculator