Factor polynomial $$ 4u^{4}-100u^{2} $$
Answer
$$ 4u^{4}-100u^{2} = 4u^{2}( u-5 )( u+5 ) $$
Explanation
Step 1 :
After factoring out $ 4u^{2} $ we have:
$$ 4u^{4}-100u^{2} = 4u^{2} ( u^{2}-25 ) $$Step 2 :
Rewrite $ u^{2}-25 $ as:
$$ u^{2}-25 = (u)^2 - (5)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = u $ and $ II = 5 $ , we have:
$$ u^{2}-25 = (u)^2 - (5)^2 = ( u-5 ) ( u+5 ) $$This page was created using
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