Factor polynomial $$ 4rx^{3}-36r^{3}x $$
Answer
$$ 4rx^{3}-36r^{3}x = 4rx(x+3r)(x-3r) $$
Explanation
Step 1 :
Factor out common factor $ \color{blue}{ 4rx } $:
$$ 4rx^3-36r^3x = 4rx ( x^2-9r^2 ) $$Step 2 :
Rewrite $ x^2-9r^2 $ as:
$$ \color{blue}{ x^2-9r^2 = (x)^2 - (3r)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = x $ and $ II = 3r $ , we have:
$$ x^2-9r^2 = (x)^2 - (3r)^2 = ( x-3r ) ( x+3r ) $$This page was created using
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