Factor polynomial $$ 4n^{3}-12n^{2}+3n-9 $$
Answer
$$ 4n^{3}-12n^{2}+3n-9 = ( 4n^{2}+3 )( n-3 ) $$
Explanation
To factor $ 4n^{3}-12n^{2}+3n-9 $ we can use factoring by grouping:
Group $ \color{blue}{ 4x^{3} }$ with $ \color{blue}{ -12x^{2} }$ and $ \color{red}{ 3x }$ with $ \color{red}{ -9 }$ then factor each group.
$$ \begin{aligned} 4n^{3}-12n^{2}+3n-9 = ( \color{blue}{ 4x^{3}-12x^{2} } ) + ( \color{red}{ 3x-9 }) &= \\ &= \color{blue}{ 4x^{2}( x-3 )} + \color{red}{ 3( x-3 ) } = \\ &= (4x^{2}+3)(x-3) \end{aligned} $$This page was created using
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