Factor polynomial $$ 49z^{2}-81 $$
Answer
$$ 49z^{2}-81 = ( 7z-9 )( 7z+9 ) $$
Explanation
Rewrite $ 49z^{2}-81 $ as:
$$ 49z^{2}-81 = (7z)^2 - (9)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 7z $ and $ II = 9 $ , we have:
$$ 49z^{2}-81 = (7z)^2 - (9)^2 = ( 7z-9 ) ( 7z+9 ) $$This page was created using
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