Factor polynomial $$ 49x^{4}-4y^{2} $$
Answer
$$ 49x^{4}-4y^{2} = (7x^{2}+2y)(7x^{2}-2y) $$
Explanation
Rewrite $ 49x^4-4y^2 $ as:
$$ \color{blue}{ 49x^4-4y^2 = (7x^2)^2 - (2y)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 7x^2 $ and $ II = 2y $ , we have:
$$ 49x^4-4y^2 = (7x^2)^2 - (2y)^2 = ( 7x^2-2y ) ( 7x^2+2y ) $$This page was created using
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