Factor polynomial $$ 49x^{2}y^{6}-25 $$
Answer
$$ 49x^{2}y^{6}-25 = (7xy^{3}+5)(7xy^{3}-5) $$
Explanation
Rewrite $ 49x^2y^6-25 $ as:
$$ \color{blue}{ 49x^2y^6-25 = (7xy^3)^2 - (5)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 7xy^3 $ and $ II = 5 $ , we have:
$$ 49x^2y^6-25 = (7xy^3)^2 - (5)^2 = ( 7xy^3-5 ) ( 7xy^3+5 ) $$This page was created using
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