Rewrite $ 49x^{2}-36 $ as:
$$ 49x^{2}-36 = (7x)^2 - (6)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 7x $ and $ II = 6 $ , we have:
$$ 49x^{2}-36 = (7x)^2 - (6)^2 = ( 7x-6 ) ( 7x+6 ) $$