Factor polynomial $$ 49n^{3}-35n^{2}+28n-20 $$
Answer
$$ 49n^{3}-35n^{2}+28n-20 = ( 7n^{2}+4 )( 7n-5 ) $$
Explanation
To factor $ 49n^{3}-35n^{2}+28n-20 $ we can use factoring by grouping:
Group $ \color{blue}{ 49x^{3} }$ with $ \color{blue}{ -35x^{2} }$ and $ \color{red}{ 28x }$ with $ \color{red}{ -20 }$ then factor each group.
$$ \begin{aligned} 49n^{3}-35n^{2}+28n-20 = ( \color{blue}{ 49x^{3}-35x^{2} } ) + ( \color{red}{ 28x-20 }) &= \\ &= \color{blue}{ 7x^{2}( 7x-5 )} + \color{red}{ 4( 7x-5 ) } = \\ &= (7x^{2}+4)(7x-5) \end{aligned} $$This page was created using
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