Factor polynomial $$ 42a^{3}b^{3}+36ab^{5}-24a^{2}b^{3} $$
Answer
$$ 42a^{3}b^{3}+36ab^{5}-24a^{2}b^{3} = 6ab^{3}(7a^{2}+6b^{2}-4a) $$
Explanation
Factor out common factor $ \color{blue}{ 6ab^3 } $:
$$ 42a^3b^3+36ab^5-24a^2b^3 = 6ab^3 ( 7a^2+6b^2-4a ) $$This page was created using
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